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find

7/22 ๊ธˆ_์ฝ”๋”ฉ ํ…Œ์ŠคํŠธ ์—ฐ์Šต(Python), ์ฐจ์›์˜ ์ €์ฃผ, Robust Scaler 1. find() ๋ฌธ์ž์—ด์— ์—†๋Š” ๋ฌธ์ž ๋˜๋Š” ๋ฌธ๊ตฌ๋ฅผ ์ฐพ๊ฒŒ ๋˜์—ˆ์„ ๋•Œ index์˜ ๊ฒฝ์šฐ ์˜ค๋ฅ˜๋ฅผ ๋ฐœ์ƒ์‹œํ‚ค๊ณ  ํ”„๋กœ๊ทธ๋žจ์ด ์ข…๋ฃŒ๋ผ๋ฒ„๋ฆฌ์ง€๋งŒ, find์˜ ๊ฒฝ์šฐ "-1"๊ฐ’์„ ์ถœ๋ ฅ์‹œ์ผœ ์ฐพ์œผ๋ ค๊ณ  ํ•˜๋Š” ๋ฌธ์ž ๋˜๋Š” ๋ฌธ๊ตฌ๊ฐ€ ์—†์Œ์„ ํ‘œ์‹œํ•ด์ฃผ๊ณ  ๋‹ค์Œ ํ”„๋กœ๊ทธ๋žจ์„ ์ง„ํ–‰์‹œํ‚ด # ๋ฐฑ์ค€ 10809๋ฒˆ ์•ŒํŒŒ๋ฒณ ์ฐพ๊ธฐ # Ver. 1 S = input() # baekjoon a = 'abcdefghijklmnopqrstuvwxyz' for i in a: if i in S: print(S.index(i), end=' ') else: print('-1', end=' ') # 1 0 -1 -1 2 -1 -1 -1 -1 4 3 -1 -1 7 5 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 # Ver. 2 S = input() # baekjo.. ๋”๋ณด๊ธฐ
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